document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=764651>Question 764651</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the angle between the string attached to a flying kite and the ground is 70 degrees how far above the ground in feet is the kite if 245 ft of string has been let out </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #465653 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=465653\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Consider this a right angled triangle.<BR>\n" );
document.write( "String = Hypotenuse.<BR>\n" );
document.write( "Height the kite is above the ground = Opposite side.<BR>\n" );
document.write( "Using Sin ratio<BR>\n" );
document.write( "Sin = Opposite/Hypotenuse<BR>\n" );
document.write( "Sin(70) = Opposite/245ft<BR>\n" );
document.write( "Opposite = 245 * sin(70)<BR>\n" );
document.write( "Opposite = 230.23ft<BR>\n" );
document.write( "This is the height the kite is above the ground.<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );