document.write( "Question 764699: Find the dimensions of the rectangle that has a length 3 meters more than its width and a perimeter equal in value to its area?\r
\n" ); document.write( "\n" ); document.write( "kindly help me with these problem? thanks
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Algebra.Com's Answer #465639 by Cromlix(4381)\"\" \"About 
You can put this solution on YOUR website!
Width = x
\n" ); document.write( "Length = x + 3
\n" ); document.write( "Perimeter = 2* width + 2*length
\n" ); document.write( "Area = width * length
\n" ); document.write( "Perimeter = Area
\n" ); document.write( "2*x + 2*(x + 3) = x*(x + 3)
\n" ); document.write( "2x + 2x + 6 = x^2 + 3x
\n" ); document.write( " x^2 + 3x - 4x - 6 = 0
\n" ); document.write( " x^2 - x - 6 = 0
\n" ); document.write( " (x + 2)(x - 3) = 0
\n" ); document.write( "x + 2 = 0
\n" ); document.write( "x = -2 (No answer x<0)
\n" ); document.write( "x - 3 = 0
\n" ); document.write( "x = 3.
\n" ); document.write( "So, width = 3m
\n" ); document.write( " length = 6m.
\n" ); document.write( "Proof:
\n" ); document.write( "Perimeter = Area
\n" ); document.write( "2*3 + 2*6 = 3*6
\n" ); document.write( " 18m = 18m
\n" ); document.write( "Hope this helps.
\n" ); document.write( ":-)
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