document.write( "Question 764699: Find the dimensions of the rectangle that has a length 3 meters more than its width and a perimeter equal in value to its area?\r
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document.write( "kindly help me with these problem? thanks \n" );
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Algebra.Com's Answer #465639 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Width = x \n" ); document.write( "Length = x + 3 \n" ); document.write( "Perimeter = 2* width + 2*length \n" ); document.write( "Area = width * length \n" ); document.write( "Perimeter = Area \n" ); document.write( "2*x + 2*(x + 3) = x*(x + 3) \n" ); document.write( "2x + 2x + 6 = x^2 + 3x \n" ); document.write( " x^2 + 3x - 4x - 6 = 0 \n" ); document.write( " x^2 - x - 6 = 0 \n" ); document.write( " (x + 2)(x - 3) = 0 \n" ); document.write( "x + 2 = 0 \n" ); document.write( "x = -2 (No answer x<0) \n" ); document.write( "x - 3 = 0 \n" ); document.write( "x = 3. \n" ); document.write( "So, width = 3m \n" ); document.write( " length = 6m. \n" ); document.write( "Proof: \n" ); document.write( "Perimeter = Area \n" ); document.write( "2*3 + 2*6 = 3*6 \n" ); document.write( " 18m = 18m \n" ); document.write( "Hope this helps. \n" ); document.write( ":-) \n" ); document.write( " |