document.write( "Question 764698:
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document.write( "Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B? \n" );
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Algebra.Com's Answer #465631 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Part A 14.00% per annum ------------- Amount invested =x \n" ); document.write( "Paert B 11.00% per annum ------------ Amount invested = y \n" ); document.write( " 1390 Rs.0 \n" ); document.write( "Interest-----Rs. 3,508 for 2 years. So for 1 year 1754.00 \n" ); document.write( " \n" ); document.write( "Part A 14.00% per annum ---x \n" ); document.write( "Paert B 11.00% per annum ---y \n" ); document.write( "Total investment \n" ); document.write( "x + 1 y= 13900 -------------1 \n" ); document.write( "Interest on both investments \n" ); document.write( "14.00% x + 11.00% y= 1754 \n" ); document.write( "Multiply by 100 \n" ); document.write( "14 x + 11 y= 175400.00 --------2 \n" ); document.write( "Multiply (1) by -14 \n" ); document.write( "we get \n" ); document.write( "-14 x -14 y= -194600.00 \n" ); document.write( "Add this to (2) \n" ); document.write( "0 x -3 y= -19200 \n" ); document.write( "divide by -3 \n" ); document.write( " y = 6400 \n" ); document.write( "Part A 14.00% $ 7500 \n" ); document.write( "Paert B 11.00% $ 6400 \n" ); document.write( " \n" ); document.write( "CHECK \n" ); document.write( "7500 --------- 14.00% ------- 1050.00 \n" ); document.write( "6400 ------------- 11.00% ------- 704.00 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |