document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=764686>Question 764686</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the probability of obtaining either a heart or a diamond in a single blind draw from a standard deck of cards?\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "I really need help to understand how to first set up this problem. I know that there are 13 of each suit. So the hearts would be 13/52 but would the diamonds also be 13/52 or do you subtract 13 from the 52. In other words would the diamonds be 13/39. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #465602 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=465602\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> either a hear or a diamond would be 13/52 + 13/52 = 26/52<BR>\n" );
document.write( "p(a or b) = p(a) + p(b) - p(a and b)<BR>\n" );
document.write( "p (a and b) would be the probability of drawing a heart and a diamond with one draw which is impossible, so the probability of p(a and b), in this case, is equal to 0.<BR>\n" );
document.write( "you have 13 hearts in the deck and you have 13 diamonds in the deck and you have 0 cards that are both a heart and a diamond.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );