document.write( "Question 764673: A chemist has 600 mL of solution that is 25% acid. She wants to make a solution that is 40% acid. How much acid should she add to the original solution? \n" ); document.write( "
Algebra.Com's Answer #465587 by josgarithmetic(39616)![]() ![]() ![]() You can put this solution on YOUR website! {amount of pure acid}/{amount of solution}={concentration of adjusted solution}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "L = 25%, concentration of available acid solution \n" ); document.write( "T = 40% acid \n" ); document.write( "R = 600, the volume ml. of available solution \n" ); document.write( "v = ml. volume of 100% acid to add to get T as result. UNKNOWN.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Solve for v. \n" ); document.write( " \n" ); document.write( " |