document.write( "Question 764673: A chemist has 600 mL of solution that is 25% acid. She wants to make a solution that is 40% acid. How much acid should she add to the original solution? \n" ); document.write( "
Algebra.Com's Answer #465587 by josgarithmetic(39616)\"\" \"About 
You can put this solution on YOUR website!
{amount of pure acid}/{amount of solution}={concentration of adjusted solution}\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "L = 25%, concentration of available acid solution
\n" ); document.write( "T = 40% acid
\n" ); document.write( "R = 600, the volume ml. of available solution
\n" ); document.write( "v = ml. volume of 100% acid to add to get T as result. UNKNOWN.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28L%2AR%2B100%2Av%29%2F%28R%2Bv%29=T\"
\n" ); document.write( "Solve for v.
\n" ); document.write( "
\n" ); document.write( "
\n" );