document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=764636>Question 764636</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write the product in standard form.<BR>\n" );
document.write( "( 9 + 5i)( 9 + 8i) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #465555 by </B><A HREF=/tutors/aboutme.mpl?userid=DrBeeee><B>DrBeeee(684)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DrBeeee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=465555\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given:<BR>\n" );
document.write( "(1) (9+5i)*(9+8i)<BR>\n" );
document.write( "You multiply this the same as you FOIL two binomials, treating the real and imaginary parts as if they were two different variables.<BR>\n" );
document.write( "(2) (9+5i)*(9+8i) = 9*9 + 9*8i + 5i*9 + 5i*8i or after multiplying <BR>\n" );
document.write( "(3) (9+5i)*(9+8i) = 81 + 72i + 45i + 40i^2 and after adding the imaginary parts and using the fact that i^2 = -1 we get <BR>\n" );
document.write( "(4) (9+5i)*(9+8i) = 81 + 117i - 40 or after adding the real parts we get <BR>\n" );
document.write( "the final answer<BR>\n" );
document.write( "(5) (9+5i)*(9+8i) = 41 + 117i </SPAN>\n" );
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