document.write( "Question 764618: Factor (2x+y)^2-49 \n" ); document.write( "
Algebra.Com's Answer #465546 by DrBeeee(684)\"\" \"About 
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Given:
\n" ); document.write( "(1) (2x+y)^2-49
\n" ); document.write( "This expression is the difference of two perfect squares which factors into the the product of the sum and difference of their square roots. For example
\n" ); document.write( "(2) (a^2-b^2) = (a+b)*(a-b)
\n" ); document.write( "In your case
\n" ); document.write( "(3) a^2 = (2x+y)^2 or
\n" ); document.write( "(4) a = 2x+y and
\n" ); document.write( "(5) b^2 = 49 or
\n" ); document.write( "(6) b = 7
\n" ); document.write( "Then the given expression of (1) factors into
\n" ); document.write( "(7) (2x+y+7)*(2x+y-7}
\n" ); document.write( "Let's FOIL (7) to see if we get (1).
\n" ); document.write( "(8) (2x+y+7)*(2x+y-7} = (2x+y)*(2x+y)-7*(2x+y)+7*(2x+y)+7*(-7} or
\n" ); document.write( "(9) (2x+y+7)*(2x+y-7} = (2x+y)^2 -7*(2x+y)+7*(2x+y) -49 or
\n" ); document.write( "(10) (2x+y+7)*(2x+y-7} = (2x+y)^2 -49 which is the same as (1)
\n" ); document.write( "Answer: (2x+y)^2-49 = (2x+y+7)*(2x+y-7}\r
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