document.write( "Question 764618: Factor (2x+y)^2-49 \n" ); document.write( "
Algebra.Com's Answer #465546 by DrBeeee(684)![]() ![]() ![]() You can put this solution on YOUR website! Given: \n" ); document.write( "(1) (2x+y)^2-49 \n" ); document.write( "This expression is the difference of two perfect squares which factors into the the product of the sum and difference of their square roots. For example \n" ); document.write( "(2) (a^2-b^2) = (a+b)*(a-b) \n" ); document.write( "In your case \n" ); document.write( "(3) a^2 = (2x+y)^2 or \n" ); document.write( "(4) a = 2x+y and \n" ); document.write( "(5) b^2 = 49 or \n" ); document.write( "(6) b = 7 \n" ); document.write( "Then the given expression of (1) factors into \n" ); document.write( "(7) (2x+y+7)*(2x+y-7} \n" ); document.write( "Let's FOIL (7) to see if we get (1). \n" ); document.write( "(8) (2x+y+7)*(2x+y-7} = (2x+y)*(2x+y)-7*(2x+y)+7*(2x+y)+7*(-7} or \n" ); document.write( "(9) (2x+y+7)*(2x+y-7} = (2x+y)^2 -7*(2x+y)+7*(2x+y) -49 or \n" ); document.write( "(10) (2x+y+7)*(2x+y-7} = (2x+y)^2 -49 which is the same as (1) \n" ); document.write( "Answer: (2x+y)^2-49 = (2x+y+7)*(2x+y-7}\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |