document.write( "Question 764499: the function f(x) = x^2 + 6x +20 + k(x^2 -3x -12) where k is real
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document.write( "find the value of k and the value of p given that the minimum value of f(x) is p and that f(-2) =p
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document.write( "the answers are 2/7 anf 80/7\r
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document.write( "i am happy if you just explain to me what to do, even briefly. \n" );
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Algebra.Com's Answer #465504 by Edwin McCravy(20055)![]() ![]() You can put this solution on YOUR website! the function f(x) = x^2 + 6x +20 + k(x^2 -3x -12) where k is real \n" ); document.write( "find the value of k and the value of p given that the minimum value of f(x) is p and that f(-2) =p \n" ); document.write( "the answers are 2/7 and 80/7\r \n" ); document.write( "\n" ); document.write( "i am happy if you just explain to me what to do, even briefly. \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "f(x) = x² + 6x + 20 + k(x² - 3x - 12)\r\n" ); document.write( "\r\n" ); document.write( "f(x) = x² + 6x + 20 + kx² - 3kx - 12k\r\n" ); document.write( "\r\n" ); document.write( "f(x) = x² + kx² + 6x - 3kx + 20 - 12k\r\n" ); document.write( "\r\n" ); document.write( "f(x) = (1 + k)x² + (6 - 3k)x + 20 - 12k\r\n" ); document.write( "\r\n" ); document.write( "We are told that f(-2) = p, so\r\n" ); document.write( "\r\n" ); document.write( "f(-2) = (1 + k)(-2)² + (6 - 3k)(-2) + 20 - 12k = p\r\n" ); document.write( "\r\n" ); document.write( " (1 + k)(4) - 12 + 6k + 20 - 12k = p\r\n" ); document.write( "\r\n" ); document.write( " 4 + 4k + 8 - 6k = p\r\n" ); document.write( "\r\n" ); document.write( " 12 - 2k = p\r\n" ); document.write( "\r\n" ); document.write( "The minimum value of f(x) = ax² + bx + c is\n" ); document.write( " |