document.write( "Question 764513: The nth term of a geometric term is 3^-n, the unlimited sum of the sequence is?\r
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Algebra.Com's Answer #465502 by ramkikk66(644) $\"\"$ $\"About$

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document.write( "nth term is given is 3^-n or 1/3^n. So the first term is 1/3, the second is 1/3^2\r\n" );
document.write( "and so on.\r\n" );
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document.write( "The series is: 1/3,1/9,1/27... to infinity.\r\n" );
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document.write( "It is an infinite geometric progression with 1st term a as 1/3 and the common \r\n" );
document.write( "ratio r as 1/3.\r\n" );
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document.write( "The formula for the sum to infinity of such a progression is given by\r\n" );
document.write( "S = a / (1 - r) (I'm not including the proof for this here)\r\n" );
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document.write( "So here it is \r\n" );
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document.write( "The answer is \r\n" );
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document.write( ":)\r\n" );
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