document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=8411>Question 8411</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you work this problem:\r<BR>\n" );
document.write( "\n" );
document.write( "Solve for x in this equation:<BR>\n" );
document.write( "(2/3)^x = 9/4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #4655 by </B><A HREF=/tutors/aboutme.mpl?userid=khwang><B>khwang(438)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=khwang><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=4655\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  (2/3)^x = 9/4<BR>\n" );
document.write( " <BR>\n" );
document.write( " Since 9/4 = (3/2)^2 and<BR>\n" );
document.write( " (3/2) = (2/3)^(-1)\r<BR>\n" );
document.write( "\n" );
document.write( " So, 9/4 = (3/2)^2 = [(2/3)^(-1)]^2 = (2/3)^(-2)<BR>\n" );
document.write( " and we get  (2/3)^x = (2/3)^(-2)<BR>\n" );
document.write( " <BR>\n" );
document.write( " Therefore ,by comparing the exponent,<BR>\n" );
document.write( " we obtain x = -2. <BR>\n" );
document.write( " (or by taking the logarithm with base 2/3 on<BR>\n" );
document.write( " both sides]\r<BR>\n" );
document.write( "\n" );
document.write( "  Kenny\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );