document.write( "Question 764425: I am having trouble setting up the problem/equations for this question... Deoraj Bharath wishes to mix coffee worth $6 per lb with coffee worth $3 per lb to get 90 lb of a mixture worth $4 per lb. How many pounds of the $6 and the $3 coffees will be needed? Can you please help me set up and solve?
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Algebra.Com's Answer #465427 by josgarithmetic(39617) $\"\"$ $\"About$

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Deoraj has two coffees, each of a different strength ---- this strength being PRICE. One coffee is L dollars per pound, and the other coffee is H dollars per pound. The person wants a M pounds of a blend which is T dollars per pound. The question is, how many pounds, u and v are needed? The u and v are the pounds of the L and the H coffees respectively.\r
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\n" ); document.write( "\n" ); document.write( "ACCOUNT FOR PRICES: $\"highlight%28%28Lu%2BHv%29%2FM=T%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "ACCOUNT FOR POUNDAGE: $\"highlight%28u%2Bv=M%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "The two equations form a system. Solve for u and v. \n" ); document.write( "

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