document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=65791>Question 65791</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0201812525/algebrahomeworkh>Algebra and Trigonometry</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> how do you write an equation of the line containing the given point and parallel to the given line?\r<BR>\n" );
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document.write( "(3,7);x+2y=6\r<BR>\n" );
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document.write( "(2,-1);5x-7y=8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #46540 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=46540\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> FIRST WE NEED TO FIND THE SLOPE OF THE LINE  THUS<BR>\n" );
document.write( "X+2Y=6<BR>\n" );
document.write( "2Y=-X+6<BR>\n" );
document.write( "Y=-X/2+6/2<BR>\n" );
document.write( "Y=-X/2+3 THUS THE SLOPE OF THIS LINE IS -1/2. <BR>\n" );
document.write( "SO THE LINE PARRALLEL TO THIS LINE MUST ALSO HAVE A SLOPE OF -1/2.<BR>\n" );
document.write( "TO FIND THE EQUATION FOR THIS LINE WE SUBSTITUTE 3 FOR X & 7 FOR Y INTHE LINE FORMULA Y=mX+b THUS:<BR>\n" );
document.write( "7=-3/2+b<BR>\n" );
document.write( "b=7+3/2<BR>\n" );
document.write( "b=7+1.5<BR>\n" );
document.write( "b=8.5 THUS THE FORMULA FOR THE LINE WITH A SLOPE OF -1/2 AND PASSING THROUGH THE POINT (3,7) IS:<BR>\n" );
document.write( "Y=-X/2+8.5 <BR>\n" );
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document.write( "5X-7Y=8 AGAIN FIND THE SLOPE<BR>\n" );
document.write( "-7Y=-5X+8<BR>\n" );
document.write( "Y=-5X/-7+8/-7<BR>\n" );
document.write( "Y=-5/7X-8/7 THIS LINE HAS A SLOPE OF -5/7.<BR>\n" );
document.write( "AGAIN SUBSTITUTE THE X & Y VALUES OF THE POINT AND FIND THE Y INTYERCEPT OF THIS LINE<BR>\n" );
document.write( "Y=mX+b<BR>\n" );
document.write( "-1=-5/7*2+b<BR>\n" );
document.write( "b=-10/7+1<BR>\n" );
document.write( "b=-(10+7)/7<BR>\n" );
document.write( "b=-17/7 THUS THE EQUATION FOR THIS LINE IS <BR>\n" );
document.write( "Y=-5/7X-17/7<BR>\n" );
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