document.write( "Question 764362: what rate of interest compounded annually is required to double and investment in 23 years?
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Algebra.Com's Answer #465391 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! what rate of interest compounded annually is required to double and investment in 23 years? \n" ); document.write( "*** \n" ); document.write( "Compound interest formula: \n" ); document.write( "A=P(1+i)^n, P=initial investment, i=interest rate per period, n=number of compound periods, A=amount after n periods \n" ); document.write( "A/P=(1+i)^n \n" ); document.write( ".. \n" ); document.write( "For given problem: \n" ); document.write( "A/P=2 \n" ); document.write( "i=? \n" ); document.write( "n=23 \n" ); document.write( ".. \n" ); document.write( "2=(1+i)^23 \n" ); document.write( "take log of both sides \n" ); document.write( "log2=23log(1+i) \n" ); document.write( "log(1+i)=log2/23≈0.013088 \n" ); document.write( "convert to exponential form: (base(10) raised to log of number(0.013088)=number(1+i) \n" ); document.write( "10^(0.013088)=1+i \n" ); document.write( "1.030595≈1+i \n" ); document.write( "i≈.0306≈3.06% \n" ); document.write( "rate of interest compounded annually required to double and investment in 23 years=3.06% \n" ); document.write( "check: \n" ); document.write( "(1+i)^23=(1.0306)^23≈2 \n" ); document.write( " \n" ); document.write( " |