document.write( "Question 764362: what rate of interest compounded annually is required to double and investment in 23 years?
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #465391 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
what rate of interest compounded annually is required to double and investment in 23 years?
\n" ); document.write( "***
\n" ); document.write( "Compound interest formula:
\n" ); document.write( "A=P(1+i)^n, P=initial investment, i=interest rate per period, n=number of compound periods, A=amount after n periods
\n" ); document.write( "A/P=(1+i)^n
\n" ); document.write( "..
\n" ); document.write( "For given problem:
\n" ); document.write( "A/P=2
\n" ); document.write( "i=?
\n" ); document.write( "n=23
\n" ); document.write( "..
\n" ); document.write( "2=(1+i)^23
\n" ); document.write( "take log of both sides
\n" ); document.write( "log2=23log(1+i)
\n" ); document.write( "log(1+i)=log2/23≈0.013088
\n" ); document.write( "convert to exponential form: (base(10) raised to log of number(0.013088)=number(1+i)
\n" ); document.write( "10^(0.013088)=1+i
\n" ); document.write( "1.030595≈1+i
\n" ); document.write( "i≈.0306≈3.06%
\n" ); document.write( "rate of interest compounded annually required to double and investment in 23 years=3.06%
\n" ); document.write( "check:
\n" ); document.write( "(1+i)^23=(1.0306)^23≈2
\n" ); document.write( "
\n" ); document.write( "
\n" );