document.write( "Question 65805This question is from textbook An Incremental Development
\n" );
document.write( ": Solve\r
\n" );
document.write( "\n" );
document.write( "x^2 + y^2 = 25\r
\n" );
document.write( "\n" );
document.write( "x - y = 1 \n" );
document.write( "
Algebra.Com's Answer #46536 by uma(370)![]() ![]() ![]() You can put this solution on YOUR website! x^2 + y^2 = 25------------(1) \n" ); document.write( "x - y = 1 \n" ); document.write( "==> x = y+1 \n" ); document.write( "Plugging in this value in (1), \n" ); document.write( "(y+1)^2 + y^2 = 25 \n" ); document.write( "==> y^2 + 2y + 1 + y^2 = 25 \n" ); document.write( "==> 2y^2 + 2y + 1 - 25 = 0 \n" ); document.write( "==> 2y^2 + 2y - 24 = 0 \n" ); document.write( "==> y^2 + y - 12 = 0 [dividing by 2 throughout] \n" ); document.write( "==> y^2 + 4y - 3y - 12 = 0 \n" ); document.write( "==> y(y+4) - 3(y+4) = 0 \n" ); document.write( "==> (y+4)(y-3) = 0 \n" ); document.write( "==> y+4 = 0 or y - 3 = 0 \n" ); document.write( "==> y = -4 or y = 3 \n" ); document.write( "==> x = -4+1 or x = 3+1 \n" ); document.write( "==> x = -3 or x = 4\r \n" ); document.write( "\n" ); document.write( "Thus x = -3 and y = -4 and x = 4 and y = 3 are the two sets of solutions.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Good luck!!! \n" ); document.write( " \n" ); document.write( " |