document.write( "Question 764323: If you place 1 before a number, the new number is 3 times as large as the original number. What is the original number? \n" ); document.write( "
Algebra.Com's Answer #465353 by josgarithmetic(39620)\"\" \"About 
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This seems to be an open ended problem. We are not given how many digits the original number. \r
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\n" ); document.write( "\n" ); document.write( "ONE DIGIT, U
\n" ); document.write( "Putting 1 in front, \"1%2A10\",
\n" ); document.write( "\"1%2A10%2BU=3U\"
\n" ); document.write( "\"U=5\" which seems to work.\r
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\n" ); document.write( "\n" ); document.write( "TWO DIGIT, TU
\n" ); document.write( "Putting 1 in front, \"1%2A100\",
\n" ); document.write( "\"1%2A100%2BT%2A10%2BU=3U\"
\n" ); document.write( "simplify to
\n" ); document.write( "\"50=10T%2BU\", which when examined for the digits possible to satisfy, becomes \"T=5\" and \"U=0\";
\n" ); document.write( "\"TU+=+50\" is the only two digit number.\r
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\n" ); document.write( "\n" ); document.write( "You can try similar process for three and more digit numbers.
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