document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=65809>Question 65809</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/093979862x/algebrahomeworkh>An Incremental Development</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Solve by completing the square\r<BR>\n" );
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document.write( "2x^2 + 2x = -3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #46534 by </B><A HREF=/tutors/aboutme.mpl?userid=uma><B>uma(370)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=uma><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=46534\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x^2 + 2x = -3<BR>\n" );
document.write( "Dividing by 2 throughout,<BR>\n" );
document.write( "x^2 + x = -3/2<BR>\n" );
document.write( "==> x^2 + x +1/4 = -3/2 + 1/4 [adding 1/4 to both the sides to complete the square in the left side]<BR>\n" );
document.write( "==> (x+1/2)^2 = -5/4<BR>\n" );
document.write( "==> (x+1/2) = +/- sqrt(-5/4)<BR>\n" );
document.write( "==> X = -1/2 +/- SQRT(-5/4)\r<BR>\n" );
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document.write( "x = -1/2 +/- sqrt(-5/4)\r<BR>\n" );
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document.write( "Good Luck!!!\r<BR>\n" );
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document.write( "Good Luck!!!<BR>\n" );
document.write( " </SPAN>\n" );
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