document.write( "Question 763978: The diagonal of a picture frame is 13 inches. If the length of the frame is 7 inches greater than its width, find the dimensions of the frame. \n" ); document.write( "
Algebra.Com's Answer #465275 by Cromlix(4381)\"\" \"About 
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Width = x
\n" ); document.write( "Length = x + 7
\n" ); document.write( "Right angled triangle.
\n" ); document.write( "Diagonal = Hypotenuse.
\n" ); document.write( "x^2 + (x + 7)^2 = 13^2
\n" ); document.write( "x^2 + x^2 + 14x + 49 = 169
\n" ); document.write( " 2x^2 + 14x - 120 = 0
\n" ); document.write( " (2x - 10)(x + 12) = 0
\n" ); document.write( "x + 12 = 0
\n" ); document.write( "x + -12 (no answer)
\n" ); document.write( "2x - 10 = 0
\n" ); document.write( " 2x = 10
\n" ); document.write( " x = 5.
\n" ); document.write( "So, Width = 5 inches
\n" ); document.write( "Length = 12 inches
\n" ); document.write( "Hope this helps.
\n" ); document.write( ":-)\r
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