document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=764014>Question 764014</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write an equation in slope-intercept form for an equation of a line perpendicular to y=-3x+1 and that intersects at point (1, 2/3). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #465259 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=465259\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Gradients of lines that are perpendicular<BR>\n" );
document.write( "have gradients (slopes) that multiply<BR>\n" );
document.write( "together to give -1<BR>\n" );
document.write( "y = -3x + 1<BR>\n" );
document.write( "Gradient (Slope) = - 3<BR>\n" );
document.write( "So, gradient of other line = 1/3<BR>\n" );
document.write( "Using equation:<BR>\n" );
document.write( "y - b = m(x - a)  and (1, 2/3)<BR>\n" );
document.write( "y - 2/3 = 1/3(x - 1)<BR>\n" );
document.write( "y - 2/3 = 1/3x - 1/3<BR>\n" );
document.write( "      y = 1/3x - 1/3 + 2/3<BR>\n" );
document.write( "      y = 1/3x + 1/3<BR>\n" );
document.write( "OR<BR>\n" );
document.write( "Multiply through by 3<BR>\n" );
document.write( "3y = x + 1<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );