document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=764088>Question 764088</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The half life of Plutonium-239 is 24,00 years. This is , 1,000 grams of Plutonium-239 will take 24,000 years to decay to 500 grams. How much of the original 1,000 grams of Plutonium 238 will be after 10 years. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #465257 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=465257\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Half life = 24,000 years<BR>\n" );
document.write( "10 years/24,000 years = 0.000416<BR>\n" );
document.write( "500g * 0.000416 = 0.21g<BR>\n" );
document.write( "500g - 0.21g<BR>\n" );
document.write( "= 499.79g<BR>\n" );
document.write( "500g + 499.79g = 999.79g<BR>\n" );
document.write( "This is the quantity that will still <BR>\n" );
document.write( "remain active after 10 years. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );