document.write( "Question 764026: the length of a rectangle is 3 yd less than twice its width, and the area of the rectangle is 27^2. find the dimensions \n" ); document.write( "
Algebra.Com's Answer #465255 by Cromlix(4381)\"\" \"About 
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Width = x
\n" ); document.write( "Length = 2x - 3
\n" ); document.write( "x(2x - 3) = 27
\n" ); document.write( "2x^2 - 3x - 27 = 0
\n" ); document.write( "(2x - 9)(x + 3) = 0
\n" ); document.write( "2x - 9 = 0
\n" ); document.write( " 2x = 9
\n" ); document.write( " x = 4.5 yds
\n" ); document.write( "x + 3 = x = -3(no answer)
\n" ); document.write( "Width = 4.5 yards
\n" ); document.write( "Length = 6 yards (2(4.5) - 3)
\n" ); document.write( "Hope this helps.
\n" ); document.write( ":-) \n" ); document.write( "
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