document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=64617>Question 64617</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I really could use some help with this one.<BR>\n" );
document.write( "\"Sketch using transformations:  f(x) = -2|x+2|.  Start with the basic graph and show all stages.\"<BR>\n" );
document.write( "I know that there are supposed to be four graphs, but I just don't understand this, please help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #46523 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=46523\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I really could use some help with this one.<BR>\n" );
document.write( "\"Sketch using transformations: f(x) = -2|x+2|. Start with the basic graph and show all stages.\"<BR>\n" );
document.write( "IN PROBLEMS INVOLVING ABSOLUTE VALUES |F(X|..HERE...|X+2|,YOU HAVE TO CONSIDER 2 CASES<BR>\n" );
document.write( "1.WHEN X+2>=0.....THAT IS X>=-2.....THEN|X+2|=X+2<BR>\n" );
document.write( "2.WHEN X+2<=0.....THAT IS X<=-2.....THEN |X+2|=-(X+2)=-X-2.<BR>\n" );
document.write( "THAT IS ALL.<BR>\n" );
document.write( "FOR CASE 1.<BR>\n" );
document.write( "WE HAVE GRAPH EQN. AS <BR>\n" );
document.write( "Y=-2(X+2).......FOR X>=-2<BR>\n" );
document.write( "X=........-2........0...................5...........10......ETC<BR>\n" );
document.write( "Y=X+2......0........-4..................-14.........-24......ETC.<BR>\n" );
document.write( "PLOT THESE POINTS TO GET THE GRAPH.\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+500%2C+500%2C+-2%2C+10%2C+-30%2C+0%2C+-2%28x%2B2%29%29+ ALIGN=MIDDLE  ALT=\"+graph%28+500%2C+500%2C+-2%2C+10%2C+-30%2C+0%2C+-2%28x%2B2%29%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "FOR CASE 2.<BR>\n" );
document.write( "WE HAVE EQN. OF GRAPH AS<BR>\n" );
document.write( "Y=-2(-X-2)=2(X+2)...........FOR X<=-2<BR>\n" );
document.write( "X=..............-10............-5..............-2<BR>\n" );
document.write( "Y=2(X+2)=.......-16............-6..............0<BR>\n" );
document.write( "PLOT THE POINTS TO GET THE GRAPH . IT WILL LOOK AS SHOWN BELOW.\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+500%2C+500%2C+-10%2C+-2%2C+-10%2C+10%2C+2%28x%2B2%29%29+ ALIGN=MIDDLE  ALT=\"+graph%28+500%2C+500%2C+-10%2C+-2%2C+-10%2C+10%2C+2%28x%2B2%29%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "YOU MAY PLOT BOTH ON SAME GRAPH,THOUGH I SHOWED 2 GRAPHS<BR>\n" );
document.write( "IT WILL BE AN INVERTED V WITH VERTEX OR MAXIMUM AS Y=0 AT X=-2 AND GOING FURTHER NEGATIVE AS X INCREASES OR DECREASES. <BR>\n" );
document.write( "I know that there are supposed to be four graphs, but I just don't understand this, please help! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );