document.write( "Question 764051: Solve. Check for extraneous solutions.\r
\n" ); document.write( "\n" ); document.write( "\"6x=sqrt%2824%2B12x%29\"\r
\n" ); document.write( "\n" ); document.write( "A. -2/3\r
\n" ); document.write( "\n" ); document.write( "B. -1\r
\n" ); document.write( "\n" ); document.write( "C. 1 and -2/3\r
\n" ); document.write( "\n" ); document.write( "D. 1
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Algebra.Com's Answer #465215 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Your question equation was adjusted according to ability to match at least one of your choices.\r
\n" ); document.write( "\n" ); document.write( "Squaring both sides and dividing by 12, you get: \"3x%5E2=2%2Bx\",
\n" ); document.write( "\"3x%5E2-x-2=0\"
\n" ); document.write( "using general solution to quadratic formula,\r
\n" ); document.write( "\n" ); document.write( "\"x=%281%2B-+sqrt%281-4%2A3%2A%28-2%29%29%29%2F6\"
\n" ); document.write( "\"x=-2%2F3\" or \"x=1\"\r
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\n" ); document.write( "Your originally given equation would properly be written in text and tags, this way:
\n" ); document.write( "6x=sqrt(24+12x)
\n" ); document.write( "and then using triple closing brackets on the right side and triple opening brackets on the left side,\r
\n" ); document.write( "\n" ); document.write( "\"6x=sqrt%2824%2B12x%29\"
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