document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=764120>Question 764120</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The present age of a woman is 3 years more than three times the age of her daughter. Three years hence, the woman's age will be 10 years more than twice the age of her daughter. Find their present age. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #465209 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39618)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=465209\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Now:<BR>\n" );
document.write( "w=3+3d\r<BR>\n" );
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document.write( "Now Plus 3 years:<BR>\n" );
document.write( "w+3=10+2(d+3)\r<BR>\n" );
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document.write( "More than one way to continue.  <BR>\n" );
document.write( "The \"hence\" equation,<BR>\n" );
document.write( "w=-3+10+2d+6<BR>\n" );
document.write( "w=13+2d\r<BR>\n" );
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document.write( "3+3d=w=13+2d<BR>\n" );
document.write( "3+d=13<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28d=10%29 ALIGN=MIDDLE  ALT=\"highlight%28d=10%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > meaning <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28w=33%29 ALIGN=MIDDLE  ALT=\"highlight%28w=33%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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