document.write( "Question 764092: A container has 1 red marble 2 green marbles 3 yellow marbles and 4 orange marbles. You select 2 marbles without replacement. \r
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document.write( "Find:
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document.write( "---Probability of selecting 2 orange marbles.\r
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document.write( "--Probability of selecting 2 red marbles.\r
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document.write( "--Probability of selecting atleast 1 red marble.\r
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document.write( "---Probability that the second marble is yellow given the first marble is green. \n" );
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Algebra.Com's Answer #465196 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A container has 1 red marble 2 green marbles 3 yellow marbles and 4 orange marbles. You select 2 marbles without replacement. \n" ); document.write( "Find: \n" ); document.write( "---Probability of selecting 2 orange marbles = 4C2/10C2 = 6/45 = 2/15 \n" ); document.write( "------------------------------------------------------ \n" ); document.write( "--Probability of selecting 2 red marbles = 0/45 = 0 \n" ); document.write( "------------------------------------------------------ \n" ); document.write( "--Probability of selecting atleast 1 red marble::: \n" ); document.write( " 1 - 9C2/10C2 = 1-36/45 = 9/45 = 1/5 \n" ); document.write( "------------------------------------------------------- \n" ); document.write( "---Probability that the second marble is yellow given the first marble is green. \n" ); document.write( "= P(yellow AND green)/P(green) = [(3*2)/10C2]/[2/10] = (6/45)/(1/5) = 2/3 \n" ); document.write( "--------------------------------------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "======================= \n" ); document.write( " \n" ); document.write( " |