document.write( "Question 764092: A container has 1 red marble 2 green marbles 3 yellow marbles and 4 orange marbles. You select 2 marbles without replacement. \r
\n" ); document.write( "\n" ); document.write( "Find:
\n" ); document.write( "---Probability of selecting 2 orange marbles.\r
\n" ); document.write( "\n" ); document.write( "--Probability of selecting 2 red marbles.\r
\n" ); document.write( "\n" ); document.write( "--Probability of selecting atleast 1 red marble.\r
\n" ); document.write( "\n" ); document.write( "---Probability that the second marble is yellow given the first marble is green.
\n" ); document.write( "

Algebra.Com's Answer #465196 by stanbon(75887)\"\" \"About 
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A container has 1 red marble 2 green marbles 3 yellow marbles and 4 orange marbles. You select 2 marbles without replacement.
\n" ); document.write( "Find:
\n" ); document.write( "---Probability of selecting 2 orange marbles = 4C2/10C2 = 6/45 = 2/15
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\n" ); document.write( "--Probability of selecting 2 red marbles = 0/45 = 0
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\n" ); document.write( "--Probability of selecting atleast 1 red marble:::
\n" ); document.write( " 1 - 9C2/10C2 = 1-36/45 = 9/45 = 1/5
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\n" ); document.write( "---Probability that the second marble is yellow given the first marble is green.
\n" ); document.write( "= P(yellow AND green)/P(green) = [(3*2)/10C2]/[2/10] = (6/45)/(1/5) = 2/3
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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