document.write( "Question 764034: A quadratic equation has a parable that has the roots x = 3 and x = -5. It passes through the point (1, -12). Determine its equation
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Algebra.Com's Answer #465172 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A quadratic equation has a parabola that has the roots x = 3 and x = -5. \n" ); document.write( " It passes through the point (1, -12). \n" ); document.write( " Determine it's equation. \n" ); document.write( ": \n" ); document.write( "Using the form ax^2 + bx + c = y, write equation for each pair \n" ); document.write( "x=3; y = 0: 9a + 3b + c = 0 \n" ); document.write( "x=-.5; y=0: .25a - .5b + c = 0 \n" ); document.write( "x=1; y=-12: a + b + c = -12 \n" ); document.write( ": \n" ); document.write( "Subtract the 3rd equation from the 1st equation \n" ); document.write( "9a + 3b + c = 0 \n" ); document.write( " a + b + c = -12 \n" ); document.write( "----------------- \n" ); document.write( "8a + 2b = 12 \n" ); document.write( "simplify, divide by 2 \n" ); document.write( "4a + b = 6 \n" ); document.write( ": \n" ); document.write( "Subtract the 3rd equation from the 2nd equation \n" ); document.write( ".25a - .5b + c = 0 \n" ); document.write( " a + b + c = -12 \n" ); document.write( "---------------- \n" ); document.write( "-.75a - 1.5b = 12 \n" ); document.write( "Simplify, divide both sides by -.75 \n" ); document.write( "a + 2b = -16 \n" ); document.write( ": \n" ); document.write( "Two 2 unknown equations we can solve with elimination \n" ); document.write( "Multiply the 1st by 2, subtract the 2nd \n" ); document.write( "8a + 2b = 12 \n" ); document.write( " a + 2b = -16 \n" ); document.write( "-----------------subtraction eliminates b, find a \n" ); document.write( "7a = 28 \n" ); document.write( "a = 28/7 \n" ); document.write( "a = 4 \n" ); document.write( ": \n" ); document.write( "Find b using a + 2b = -16 \n" ); document.write( "4 + 2b = -16 \n" ); document.write( "2b = -20 \n" ); document.write( "b = -10 \n" ); document.write( ": \n" ); document.write( "Find c \n" ); document.write( "4 - 10 + c = -12 \n" ); document.write( "c = -12 + 6 \n" ); document.write( "c = -6 \n" ); document.write( ": \n" ); document.write( "Our equation: y = 4x^2 - 10x - 6 \n" ); document.write( ": \n" ); document.write( "Graphically \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |