document.write( "Question 764074: In the complex number system, solve 4x^2-2x+4=0
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document.write( "I am confused about the \" solve using the complex number system\", if I use the quadratic formula I get No real Solution, 1 +- (Square root of -60) over 4. I appreciate your help \n" );
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Algebra.Com's Answer #465171 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "That's right...there is no real solution. That means that the zeros are complex numbers rather than real numbers. Complex numbers are of the form \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "Egw to Beta kai to Sigma \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |