document.write( "Question 763999: In a survey of 9000 women, 6431 sy they change their nail polish once a week. Construct a 95% confidence interval for the population proportion of women who change their nail polish once a week\r
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document.write( "9000/6431=1.4 \n" );
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Algebra.Com's Answer #465167 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! In a survey of 9000 women, 6431 sy they change their nail polish once a week. Construct a 95% confidence interval for the population proportion of women who change their nail polish once a week \n" ); document.write( "------ \n" ); document.write( "sample proportin = p-hat = 6431/9000 = 0.71 \n" ); document.write( "---- \n" ); document.write( "ME = 1.96*sqrt[0.71*0.29/9000] = 0.0094 \n" ); document.write( "------ \n" ); document.write( "95% CI: 0.71-0.0094 < p < 0.71+0.0094 \n" ); document.write( "========================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================ \n" ); document.write( " |