document.write( "Question 764060: A cement walk of constant width is built around an 8m x 12m rectangular garden. The total area of the garden and walk is 192m^2. Find the width of the walk.\r
\n" ); document.write( "\n" ); document.write( "So far, I have gathered that the garden has an 8:12 or 2:3 ratio. \r
\n" ); document.write( "\n" ); document.write( "Thank you in advance for your help! \n" ); document.write( "

Algebra.Com's Answer #465163 by stanbon(75887) $\"\"$ $\"About$

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A cement walk of constant width is built around an 8m x 12m rectangular garden. The total area of the garden and walk is 192m^2. Find the width of the walk.
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\n" ); document.write( "Draw an elongated rectangle inside an elongated rectangle.
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\n" ); document.write( "The inside rectangle is 8 by 12 = 96 sq meters
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\n" ); document.write( "The outside rectangle is (8+2x)(12+2x) = 96 + 40x + 4x^2 sq. meters
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\n" ); document.write( "Solve: 4x^2 + 40x + 96 = 192
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\n" ); document.write( "x^2 + 10x + 24 = 48
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\n" ); document.write( "x^2 + 10x - 24 = 0
\n" ); document.write( "(x+12)(x-2) = 0
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\n" ); document.write( "Positive solution:
\n" ); document.write( "x = 2 meters
\n" ); document.write( "That is the width of the walk.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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