document.write( "Question 65780This question is from textbook Pre-Algebra
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\n" ); document.write( "23/41 divided by 25/82 - 3/10
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Algebra.Com's Answer #46514 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
Evalute the expression.\r\n" );
document.write( "23/41 divided by 25/82 - 3/10\r\n" );
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document.write( "Nate above took it that your problem is \"23%2F41\"÷\"25%2F82+-+3%2F10\"\r\n" );
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document.write( "It occurred to me that you could have\r\n" );
document.write( "meant this instead:\r\n" );
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document.write( "\"23%2F41\"÷\"%2825%2F82+-+3%2F10%29\"\r\n" );
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document.write( "Work in the parentheses first.\r\n" );
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document.write( "The LCD of 82 and 10 is 410.\r\n" );
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document.write( "So to make \"25%2F82\" have a denominator of\r\n" );
document.write( "410, we multiply it by \"5%2F5\".\r\n" );
document.write( "Also to make \"3%2F10\" have a denominator of\r\n" );
document.write( "410, we multiply it by \"41%2F41\". So we have:\r\n" );
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document.write( "\"23%2F41\"÷\"%2825%2F82%2A5%2F5+-+3%2F10%2A41%2F41%29\"\r\n" );
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document.write( "\"23%2F41\"÷\"%28125%2F410+-+123%2F410%29\"\r\n" );
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document.write( "Combine the fractions in the parentheses:\r\n" );
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document.write( "\"23%2F41\"÷\"%282%2F410%29\"\r\n" );
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document.write( "Now \"2%2F410\" reduces to \"1%2F205\" and\r\n" );
document.write( "we have\r\n" );
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document.write( "\"23%2F41\"÷\"1%2F205\"\r\n" );
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document.write( "now we invert the second fraction and \r\n" );
document.write( "change ÷ to ×\r\n" );
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document.write( " 23     205\r\n" );
document.write( "---- × -----\r\n" );
document.write( " 41      1\r\n" );
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document.write( "Cancel the 41 into the 205\r\n" );
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document.write( "         5      \r\n" );
document.write( " 23     205\r\n" );
document.write( "---- × -----\r\n" );
document.write( " 41      1\r\n" );
document.write( "  1\r\n" );
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document.write( "  23×5\r\n" );
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document.write( "  115\r\n" );
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document.write( "Edwin
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