document.write( "Question 763949: A radiator contains 10 quarts of fluid, 30% of which is antifreeze. How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 40% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #465117 by stanbon(75887)\"\" \"About 
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A radiator contains 10 quarts of fluid, 30% of which is antifreeze. How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 40% antifreeze?
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\n" ); document.write( "Equation:
\n" ); document.write( "active - active + active = active
\n" ); document.write( "0.30*10 - 0.30x + 1.00x = 0.40*10
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\n" ); document.write( "30*10 - 30x + 100x = 40*10
\n" ); document.write( "70x = 10*10
\n" ); document.write( "x = 10/7 = 1.4286 quarts (amt. to remove and replace)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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