document.write( "Question 763755: One number is 1 less than a second number. Twice the second number is
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document.write( "20 less than 4 times the first. Find the two numbers? I can never figure out how to set these equations up, could you show me the proper steps. Thank you very much. \n" );
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Algebra.Com's Answer #465033 by MathTherapy(10555)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "One number is 1 less than a second number. Twice the second number is \n" ); document.write( "20 less than 4 times the first. Find the two numbers? I can never figure out how to set these equations up, could you show me the proper steps. Thank you very much.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let the smaller, or first number be S\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then larger or second number = S + 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, 2(S + 1) = 4S - 20 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2S + 2 = 4S - 20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2S - 4S = - 20 - 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "- 2S = - 22\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "S, or smaller/first number = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Larger/second number = S + 1, or \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You can do the check!! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Further help is available, online or in-person, for a fee, obviously. Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com \n" ); document.write( " |