document.write( "Question 763755: One number is 1 less than a second number. Twice the second number is
\n" ); document.write( "20 less than 4 times the first. Find the two numbers? I can never figure out how to set these equations up, could you show me the proper steps. Thank you very much.
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Algebra.Com's Answer #465033 by MathTherapy(10555)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "One number is 1 less than a second number. Twice the second number is
\n" ); document.write( "20 less than 4 times the first. Find the two numbers? I can never figure out how to set these equations up, could you show me the proper steps. Thank you very much.\r
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\n" ); document.write( "\n" ); document.write( "Let the smaller, or first number be S\r
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\n" ); document.write( "\n" ); document.write( "Then larger or second number = S + 1\r
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\n" ); document.write( "\n" ); document.write( "Therefore, 2(S + 1) = 4S - 20 \r
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\n" ); document.write( "\n" ); document.write( "2S + 2 = 4S - 20\r
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\n" ); document.write( "\n" ); document.write( "2S - 4S = - 20 - 2\r
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\n" ); document.write( "\n" ); document.write( "- 2S = - 22\r
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\n" ); document.write( "\n" ); document.write( "S, or smaller/first number = \"%28-+22%29%2F-+2\", or \"highlight_green%2811%29\"\r
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\n" ); document.write( "\n" ); document.write( "Larger/second number = S + 1, or \"highlight_green%2812%29\"\r
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\n" ); document.write( "\n" ); document.write( "You can do the check!! \r
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\n" ); document.write( "\n" ); document.write( "Further help is available, online or in-person, for a fee, obviously. Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com
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