document.write( "Question 763749: Two cyclists, 48 miles apart, start riding toward each other at the same time. One cycles 3 times as fast as the other. If they meet 2 hours later, what is the speed (in mi/h) of the faster cyclist? \n" ); document.write( "

Algebra.Com's Answer #464982 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
You can think of one cyclist as standing still and
\n" ); document.write( "the other one approaching at the sum of their speeds
\n" ); document.write( "------------------------
\n" ); document.write( "Let $\"+s+\"$ = the speed of the slower one
\n" ); document.write( " $\"+3s+\"$ = the speed of the faster one
\n" ); document.write( "------------------------
\n" ); document.write( " $\"+48+=+%28+s+%2B+3s+%29%2A2+\"$
\n" ); document.write( " $\"+48+=+4s%2A2+\"$
\n" ); document.write( " $\"+8s+=+48+\"$
\n" ); document.write( " $\"+s+=+6+\"$
\n" ); document.write( " $\"+3s+=+18+\"$
\n" ); document.write( "The faster cyclist's speed is 18 mi/hr
\n" ); document.write( "-------------------
\n" ); document.write( "check answer:
\n" ); document.write( "Slower cyclist:
\n" ); document.write( " $\"+d%5B1%5D+=+s%2A2%0D%0A%7B%7B%7B+d%5B1%5D+=+6%2A2+\"$
\n" ); document.write( " $\"+d%5B1%5D+=12+\"$
\n" ); document.write( "Faster cyclist:
\n" ); document.write( " $\"+d%5B2%5D+=+3s%2A2+\"$
\n" ); document.write( " $\"+d%5B2%5D+=+18%2A2+\"$
\n" ); document.write( " $\"+d%5B2%5D+=+36+\"$
\n" ); document.write( " $\"+d%5B1%5D+%2B+d%5B2%5D+=+48+\"$
\n" ); document.write( "OK
\n" ); document.write( " \n" ); document.write( "

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