document.write( "Question 763654: On Monday, Dan leaves his house at 8:10 AM and bikes to the office, which is 7 miles away. He is able to bike at a constant speed of 10.5 mph.\r
\n" ); document.write( "\n" ); document.write( "On Tuesday, Dan feels lazy and decides to take the 8:16AM train to work. The train takes 13 minutes to reach the Palo Alto stop, and then it takes Dan 5 minutes to walk to work. How much time (in minutes) does he have to grab a bagel, if he wants to get to work as the same time as he did on Monday?
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Algebra.Com's Answer #464969 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "7 divided by 10.5 is 2/3. So at 10.5 miles per hour it takes 2/3 of an hour, which is to say 40 minutes to travel the 7 miles by bike. 8:10 AM plus 40 minutes is 8:50.\r
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\n" ); document.write( "\n" ); document.write( "8:16 + 13 minutes + 5 minutes = 8:34. He has the difference between 8:50 and 8:34.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "Egw to Beta kai to Sigma
\n" ); document.write( "My calculator said it, I believe it, that settles it
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