document.write( "Question 763687: Okay, so the problem is (x+2)^2=-7
\n" ); document.write( "I simplified it to (x+2)(x+2)=-7. And then I did, x^2+4x+4=-7. I added the negative 7 to the 4 making the problem x^2+4x+11=0 and then that's when I tried to use the quadratic formula but it comes out as -4 +over- radical -28 all over 2. Help me please!!!!!!!!
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Algebra.Com's Answer #464956 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Your steps are in the wrong direction. The given equation is in a form easy to solve for x. Trying to factor, or trying to put into general form is counter productive. Just solve for x without any tricks. Do you see, just by looking at the equation, the solution will contain imaginary numbers? \r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B2%29%5E2=-7\"
\n" ); document.write( "\"%28%28x%2B2%29%5E2%29%5E%281%2F2%29=%28-7%29%5E%281%2F2%29\"
\n" ); document.write( "\"%28x%2B2%29=0%2B-+sqrt%28-7%29\"
\n" ); document.write( "\"x=-2%2B-+sqrt%28-7%29\"\r
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\n" ); document.write( "\n" ); document.write( "Using \"i%5E2=-1\",
\n" ); document.write( "\"highlight%28x=2%2B-+i%2Asqrt%287%29%29\"
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