document.write( "Question 763666: The length of a rectangle is 3 centimeters less than its width. What are the dimensions of the rectangle if its area is 40 square centimeters \n" ); document.write( "
Algebra.Com's Answer #464933 by ramkikk66(644)\"\" \"About 
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document.write( "Let length be L. Width is then L+3 cm. \r\n" );
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document.write( "Area = \"L%2A%28L%2B3%29+=+L%5E2+%2B+3%2AL+=+40\"\r\n" );
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document.write( "\"L%5E2+%2B+3%2AL+-+40+=+0\"\r\n" );
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document.write( "Factorizing the left side\r\n" );
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document.write( "\"%28L+%2B+8%29%2A%28L+-+5%29+=+0\"\r\n" );
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document.write( "L = -8 or L = 5\r\n" );
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document.write( "Since L cannot be negative, length = 5 cm and therefore Width = 8 cm.\r\n" );
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document.write( "Check: Area = L*W = 5*8 = 40. Correct!\r\n" );
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