document.write( "Question 763523: When you travel to work going 60 miles per hour, you arrive there early.
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Algebra.Com's Answer #464926 by ramkikk66(644) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "Let us say the distance to work is x miles.\r\n" );
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document.write( "Case 1: Time taken to travel x miles at 60 mph, is x/60 hours\r\n" );
document.write( "Case 2: Time taken to travel x miles at 30 mph, is x/30 hours\r\n" );
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document.write( "Now it is given that x/60 is early and x/30 is late compared to the right time to arrive.\r\n" );
document.write( "Also, the amount of \"early\" time is the same as the amount of \"late\" time.\r\n" );
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document.write( "So, it means that the \"right\" time is at the midpoint or average of the 2 times.\r\n" );
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document.write( "Right time to reach work = \r\n" );
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document.write( "So you need to travel for x/40 hours, to cover the distance of x miles and reach work exactly on time.\r\n" );
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document.write( "So the average speed to be maintained = \r\n" );
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document.write( "You need to travel at  mph to reach on time.\r\n" );
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document.write( "Hope you got it. Please email me if it's still not clear.\r\n" );
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