document.write( "Question 763603: Sir/ma'am,\r
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\n" ); document.write( "\n" ); document.write( "answer is 20,15 \r
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Algebra.Com's Answer #464924 by ramkikk66(644)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Your series is: 2,7,5,9,9,1,14,13,---,--- \r\n" );
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document.write( "Pl check - is the 6th term 1 or 11?\r\n" );
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document.write( "I think there could be a typo and it is actually 11.\r\n" );
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document.write( "If so, the series is 2,7,5,9,9,11,14,13,...,... and it can be solved.\r\n" );
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document.write( "Solution:\r\n" );
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document.write( "Look at alternate terms - they form 2 separate series. \r\n" );
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document.write( "Series 1:\r\n" );
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document.write( "2,5,9,14... where the difference between successive terms keeps increasing by 1. \r\n" );
document.write( "2 + 3 = 5\r\n" );
document.write( "5 + 4 = 9\r\n" );
document.write( "9 + 5 = 14\r\n" );
document.write( "So the next term in this series is 14 + 6 = 20\r\n" );
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document.write( "Series 2:\r\n" );
document.write( "And the other series is\r\n" );
document.write( "7,9,13,... which is a simple arithmetic progression with difference as 2. So the next term in this series is 13 + 2 = 15.\r\n" );
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document.write( "So the next two terms are 20 and  15.\r\n" );
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document.write( "Hope this helps.\r\n" );
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