document.write( "Question 763332: given that w varies directly as the product of x and y and inversely as the square of z and that w=4, when x=2, y=6 and z=3. Find the w when x=1, y=4 and z=2. \n" ); document.write( "
Algebra.Com's Answer #464922 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! W = kXY/z^2 \n" ); document.write( "k = constant of variation \n" ); document.write( "To find k \n" ); document.write( "4 = k*2*6/9 \n" ); document.write( "k = 9 * 4/12 \n" ); document.write( "k = 3 \n" ); document.write( "Equation: \n" ); document.write( "W = 3XY/z^2 \n" ); document.write( "W = 3*1*4/4 \n" ); document.write( "W = 3. \n" ); document.write( " \n" ); document.write( " |