document.write( "Question 763332: given that w varies directly as the product of x and y and inversely as the square of z and that w=4, when x=2, y=6 and z=3. Find the w when x=1, y=4 and z=2. \n" ); document.write( "
Algebra.Com's Answer #464922 by Cromlix(4381)\"\" \"About 
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W = kXY/z^2
\n" ); document.write( "k = constant of variation
\n" ); document.write( "To find k
\n" ); document.write( "4 = k*2*6/9
\n" ); document.write( "k = 9 * 4/12
\n" ); document.write( "k = 3
\n" ); document.write( "Equation:
\n" ); document.write( "W = 3XY/z^2
\n" ); document.write( "W = 3*1*4/4
\n" ); document.write( "W = 3.
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