document.write( "Question 763597: The top of a rectangular cuboid has an area of 0.56 metres squared,the front is 0.12 metres squared and the end is 0.105 metres squared.How do i calculate the length.Thanks for your help. \n" ); document.write( "
Algebra.Com's Answer #464914 by ramkikk66(644)\"\" \"About 
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Let the Length, Width and Height be L, W and H metres\r
\n" ); document.write( "\n" ); document.write( "Top = L*W = 0.56 ------ eqn(1)
\n" ); document.write( "Front = L*H = 0.12 ------ eqn (2)
\n" ); document.write( "Side = W*H = 0.105 ------- eqn(3)\r
\n" ); document.write( "\n" ); document.write( "Multiplying the above 3 equations (we can do this because we know that none of the values are 0)\r
\n" ); document.write( "\n" ); document.write( "\"L%2AW%2AL%2AH%2AW%2AH+=+%28L%2AW%2AH%29%5E2+=+0.56%2A0.12%2A0.105+=+0.007056\"\r
\n" ); document.write( "\n" ); document.write( "Hence \"L%2AW%2AH+=+sqrt%280.007056%29+=+0.084\"\r
\n" ); document.write( "\n" ); document.write( "Now we can find L as \"L+=+%28L%2AW%2AH%29%2F%28W%2AH%29+=+0.084%2F0.105+=+0.8\"\r
\n" ); document.write( "\n" ); document.write( "Length = \"highlight%280.8%29\" meters.\r
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