document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=763564>Question 763564</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An athlete runs 8 miles, first at a slower speed and then at a faster speed. The total time spent running is 1 hour. If the athlete runs 1/3 hour at 6 miles per hour, find the second speed. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #464910 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=464910\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Distance = Time * Speed<BR>\n" );
document.write( "         = 1/3hr * 6mph<BR>\n" );
document.write( "         = 2 miles<BR>\n" );
document.write( "Therefore the athlete ran the 6 miles (8 - 2)<BR>\n" );
document.write( "in 2/3 hr.<BR>\n" );
document.write( "6hr/2/3 = 9mph<BR>\n" );
document.write( "Second speed = 9mph.<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-)\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );