document.write( "Question 65774: A garden area is 30ft long and 20ft wide. A path of uniform width is set around the edge. If the remaining garden area is 400ft^2, what is the width of the path?
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Algebra.Com's Answer #46491 by checkley71(8403)\"\" \"About 
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(30-2x)(20-2x)=400
\n" ); document.write( "600-40x-60x+4x^2=400
\n" ); document.write( "4x^2-100x=-600+400
\n" ); document.write( "4x^2-100x=-200
\n" ); document.write( "4x^2-100x+200=0
\n" ); document.write( "x^2-25x+50=0
\n" ); document.write( "using the quadratic equation for x we get
\n" ); document.write( "x=(-b+-sqrt[b^2-4ac])/2a
\n" ); document.write( "x=(25+-sqrt625-4*1*50])/2*1
\n" ); document.write( "x=(25+-sqrt[625-200])/2
\n" ); document.write( "x=(25+-sqrt425)/2
\n" ); document.write( "x=(25+-20.6155)/2
\n" ); document.write( "x=(25+20.6155)/2
\n" ); document.write( "x=45.6155/2
\n" ); document.write( "x=22.8 not a solution because it is longer than the garden.
\n" ); document.write( "x=(25-20.6155)/2
\n" ); document.write( "x=4.3845/2
\n" ); document.write( "x=2.19 feet for the path
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