document.write( "Question 763537: In a certain department store, which has four sizes of a specific shirt, there are 1/3 as many small shirts as medium shirts, and 1/2 as many large shirts as small shirts. If there are as many x-large shirts as large shirts, what percent of the shirts in the store are medium?
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Algebra.Com's Answer #464908 by KMST(5328)\"\" \"About 
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Let's say that there are \"x\"% medium shirts.
\n" ); document.write( "Since there are 1/3 as many small shirts as medium shirts,
\n" ); document.write( "there are \"%281%2F3%29x\"% small shirts.
\n" ); document.write( "Since there are 1/2 as many large shirts as small shirts,
\n" ); document.write( "there are \"%281%2F2%29%281%2F3%29x\"% large shirts.
\n" ); document.write( "Since there are as many x-large shirts as large shirts,
\n" ); document.write( "there are \"%281%2F2%29%281%2F3%29x\"% x-large shirts.
\n" ); document.write( "The total is, off course \"100\"%, so
\n" ); document.write( "\"x%2B%281%2F3%29x%2B%281%2F2%29%281%2F3%29x%2B%281%2F2%29%281%2F3%29x=100\"
\n" ); document.write( "Taking out \"x\" as a common factor, we get
\n" ); document.write( "\"x%281%2B%281%2F3%29%2B%281%2F2%29%281%2F3%29%2B%281%2F2%29%281%2F3%29%29=100\"
\n" ); document.write( "Multiplying and adding those fractions, we get
\n" ); document.write( "\"x%281%2B1%2F3%2B1%2F6%2B1%2F6%29=100\" --> \"x%281%2B1%2F3%2B1%2F3%29=100\" --> \"x%285%2F3%29=100\"
\n" ); document.write( "Multiplying both sides of the equation times \"3%2F5\", we get the solution.
\n" ); document.write( "\"x%285%2F3%29=100\" --> \"x=100%283%2F5%29\" --> \"x=100%2A3%2F5%29\" --> \"highlight%28x=60%29\".
\n" ); document.write( "So 60% of the shirts are medium, 20% are small, 10% are large, and the remaining 10% are extra large.
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