document.write( "Question 65775: The length of a rectangle is 1cm longer than its width. If the diaganol of rectangle is 4cm, what are the dimensions (length and width) of the rectangle?\r
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Algebra.Com's Answer #46489 by checkley71(8403)\"\" \"About 
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using the pathagorian theorum a^2+b^2=c^2 a=x, b=(x+1), c=4
\n" ); document.write( "x^2+(x+1)^2=4^2
\n" ); document.write( "x^2+x^2+2x+1=16
\n" ); document.write( "2x^2+2x-15=0 using the quadratic equation x=(-b+-sqrt[b^2-4ac])/2a
\n" ); document.write( "x=(-2+-sqrt[2^2-4*2*-15])/2*2
\n" ); document.write( "x=(-2+-sqrt[4+120])/4
\n" ); document.write( "x=(-2+-sqrt124)/4
\n" ); document.write( "x=(-2+-11.1355)/4
\n" ); document.write( "x=(-2+11.1355)/4
\n" ); document.write( "x=9.1355/4
\n" ); document.write( "x=2.2839 cm for the width.
\n" ); document.write( "length is 2.2839+1=3.2839
\n" ); document.write( "proof
\n" ); document.write( "2.2839^2+3.2839^2=4^2
\n" ); document.write( "5.216+10.784=16
\n" ); document.write( "16=16
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