document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=763562>Question 763562</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Rectangle is 5ft in length  more than width the perimeter must be at least 38 feet but no more than 60 feet find the possible dimensions of the width. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #464888 by </B><A HREF=/tutors/aboutme.mpl?userid=ramkikk66><B>ramkikk66(644)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ramkikk66><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=464888\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Rectangle is 5ft in length  more than width the perimeter must be at least 38 feet but no more than 60 feet find the possible dimensions of the width.\r<BR>\n" );
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document.write( "Let Width be W<BR>\n" );
document.write( "Length L = W + 5\r<BR>\n" );
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document.write( "Perimeter = 2*(L+W) = 2*(W+W+5) = 4*W + 10\r<BR>\n" );
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document.write( "Perimeter must be at least 38 ft. So 4*W + 10 >= 38, or 4*W >= 28\r<BR>\n" );
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document.write( "W >= 7 ft. Width must be at least 7 feet\r<BR>\n" );
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document.write( "Perimeter must be at most 60 feet. So 4*W + 10 <= 60, or 4*W <= 50\r<BR>\n" );
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document.write( "W <= 12.5 ft. Width must be at most 12.5 feet\r<BR>\n" );
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document.write( "So possible dimensions of the width are in the range of 7 feet to 12.5 feet.\r<BR>\n" );
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document.write( ":) </SPAN>\n" );
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