document.write( "Question 65765This question is from textbook Beginning Algebra
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document.write( ": Graph the following equation, using the intercept method. \r
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document.write( "2x + 3y = 6\r
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document.write( "I am a bit confusded on how to graph these since there are two variables. If I worked the problem right I came up with 1.\r
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document.write( "2x + 3y = 5
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document.write( "6-5 = 1\r
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document.write( "This is as far as I got. \n" );
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Algebra.Com's Answer #46488 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! TRO PUT THESE EQUATIONS IN THE LINE FORM WE HAVE: \n" ); document.write( "2X+3Y=6 \n" ); document.write( "3Y=-2X+6 \n" ); document.write( "Y=-2X/3+6/3 \n" ); document.write( "Y=-2X/3+2 THUS THIS LINE HAS A SLOPE OF -2/3 & A Y INTERCEPT OF 2 \n" ); document.write( "----------------------------------------------------------------------- \n" ); document.write( "2X+3Y=5 \n" ); document.write( "3Y=-2X=5 \n" ); document.write( "Y=-2X/3+5/3 THUS THIS LINE ALSO HAS A SLOPE OF -2/3 & A Y INTERCEPT OF 5/3\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "-2/3X+5/3). \r \n" ); document.write( "\n" ); document.write( " |