document.write( "Question 763575: in 5 years time a father will be twice as old as his son will be. four years ago he was three times as old as his son was. find their present ages? \n" ); document.write( "
Algebra.Com's Answer #464872 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! in 5 years time a father will be twice as old as his son will be. four years ago he was three times as old as his son was. find their present ages? \n" ); document.write( "*** \n" ); document.write( "4 yrs ago: \n" ); document.write( "x=son's age \n" ); document.write( "3x=father's age \n" ); document.write( ".. \n" ); document.write( "At present \n" ); document.write( "x+4=son'age \n" ); document.write( "3x+4=father's age \n" ); document.write( ".. \n" ); document.write( "5 yrs from now: \n" ); document.write( "x+4+5=x+9=son'age \n" ); document.write( "3x+4+5=3x+9=father's age \n" ); document.write( "3x+9=2(x+9) \n" ); document.write( "3x+9=2x+18 \n" ); document.write( "x=9 \n" ); document.write( "son's present age=x+4=13 \n" ); document.write( "father's present age=3x+4=31 \n" ); document.write( " |