document.write( "Question 763575: in 5 years time a father will be twice as old as his son will be. four years ago he was three times as old as his son was. find their present ages? \n" ); document.write( "
Algebra.Com's Answer #464872 by lwsshak3(11628)\"\" \"About 
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in 5 years time a father will be twice as old as his son will be. four years ago he was three times as old as his son was. find their present ages?
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\n" ); document.write( "4 yrs ago:
\n" ); document.write( "x=son's age
\n" ); document.write( "3x=father's age
\n" ); document.write( "..
\n" ); document.write( "At present
\n" ); document.write( "x+4=son'age
\n" ); document.write( "3x+4=father's age
\n" ); document.write( "..
\n" ); document.write( "5 yrs from now:
\n" ); document.write( "x+4+5=x+9=son'age
\n" ); document.write( "3x+4+5=3x+9=father's age
\n" ); document.write( "3x+9=2(x+9)
\n" ); document.write( "3x+9=2x+18
\n" ); document.write( "x=9
\n" ); document.write( "son's present age=x+4=13
\n" ); document.write( "father's present age=3x+4=31
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