document.write( "Question 763497: Two cars start together and travel in the same direction. One car travels twice as fast as the other. After five hours, they are 275 km apart. How fast is each car traveling? \n" ); document.write( "
Algebra.Com's Answer #464845 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "This is a rate/time/distance problem so we will use the following formula:\r
\n" ); document.write( "\n" ); document.write( "\"Rate+%2A+Time+=+Distance\"\r
\n" ); document.write( "\n" ); document.write( "Establish your terms:\r
\n" ); document.write( "\n" ); document.write( "Let \"r+\" be the rate of speed of car \"A\"
\n" ); document.write( "Let \"2r\" be the rate of speed of car \r
\n" ); document.write( "\n" ); document.write( "Let \"5r%7D%7D+be+the+distance+car+%7B%7B%7BA\" travels after \"5\" hours
\n" ); document.write( "Let \"5%282r%29+=+10r\" be the distance car \"B\" travels after \"5\" hours\r
\n" ); document.write( "\n" ); document.write( "Since car \"B\" is the faster car it will have travelled farther after \"5\" hours so:\r
\n" ); document.write( "\n" ); document.write( "Distance car \"B\" travels - distance car \"A\" travels is equal to \"275\"\r
\n" ); document.write( "\n" ); document.write( "Using our terms from above:\r
\n" ); document.write( "\n" ); document.write( "\"10r+-+5r+=+275\"
\n" ); document.write( "\"5r+=+275\"
\n" ); document.write( "\"r+=+55+kph\" \r
\n" ); document.write( "\n" ); document.write( "and \r
\n" ); document.write( "\n" ); document.write( "\"2r+=+110+kph\"\r
\n" ); document.write( "\n" ); document.write( "Car \"A\" is travelling at \"55kph\" and car \"B\" is tavelling at \"110kph\".\r
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