document.write( "Question 64576: the answer is (4e^(2/3))/3e but i need work please help\r
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document.write( "ln4x-ln3-2lnx=(1/3) \n" );
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Algebra.Com's Answer #46481 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! the answer is the answer is (4e^(2/3))/3e but i need work please help \n" ); document.write( "ln4x-ln3-2lnx=(1/3) \n" ); document.write( "USE FORMULAE \n" ); document.write( "LN(X/Y)=LN(X)-LN(Y) \n" ); document.write( "LN(X)+LN(Y)=LN(XY) \n" ); document.write( "A*LN(X)=LN(X^A) \n" ); document.write( "AND IF \n" ); document.write( "LN(X)=A \n" ); document.write( "X=E^A\r \n" ); document.write( "\n" ); document.write( "LN(4X)-LN(3)-2LN(X)= LN(4X/3)-LN(X^2)=LN[4X/3X^2)=LN[4/(3X)]=1/3 \n" ); document.write( "E^(1/3)=4/(3X) \n" ); document.write( "X=(4/3)[E^(-1/3)]=4/{3*E^(1/3)}=[4E^(2/3)]/[3*{E^(1/3)}{E^(2/3)}] \n" ); document.write( "=[4*E^(2/3)/(3E)] \n" ); document.write( " |