document.write( "Question 763409: Solution 1 consists of 80% benzene and 20% toluene. Solution 2 consists of 30% benzene and 70% toluene. \r
\n" ); document.write( "\n" ); document.write( "a) How many mL of Solution 1 must be added to 500 mL of Solution 2 in order to produce a solution that is 70% benzene?\r
\n" ); document.write( "\n" ); document.write( "b) How many mL of Solution 1 and how many mL of Solution 2 must be combined to form a 100 mL solution that is 50% benzene and 50% toluene? \r
\n" ); document.write( "\n" ); document.write( "c) Is there a combination of Solution 1 and Solution 2 that is 90% benzene and 10% toluene?
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Algebra.Com's Answer #464809 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
(a)
\n" ); document.write( "Let \"+a+\" = ml of solution 1 to be added
\n" ); document.write( "\"+.8a+\" = ml of benzene in solution 1
\n" ); document.write( "\"+.3%2A500+=+150+\" ml of benzene in solution 2
\n" ); document.write( "----------------------------------------
\n" ); document.write( "\"+%28+.8a+%2B+150+%29+%2F+%28+a+%2B+500+%29+=+.7+\"
\n" ); document.write( "\"+.8a+%2B+150+=+.7%2A%28+a+%2B+500+%29+\"
\n" ); document.write( "\"+.8a+%2B+150+=+.7a+%2B+350+\"
\n" ); document.write( "\"+.1a+=+200+\"
\n" ); document.write( "\"+a+=+2000+\"
\n" ); document.write( "2000 ml ( 2 l ) of solution 1 must be added
\n" ); document.write( "check:
\n" ); document.write( "\"+%28+.8a+%2B+150+%29+%2F+%28+a+%2B+500+%29+=+.7+\"
\n" ); document.write( "\"+%28+.8%2A2000+%2B+150+%29+%2F+%28+2000+%2B+500+%29+=+.7+\"
\n" ); document.write( "\"+%28+1600+%2B+150+%29+%2F+2500+=+.7+\"
\n" ); document.write( "\"+1750+=+.7%2A2500+\"
\n" ); document.write( "\"+1750+=+1750+\"
\n" ); document.write( "OK
\n" ); document.write( "----------
\n" ); document.write( "(b)
\n" ); document.write( "Let \"+a+\" = ml of solution 1 needed
\n" ); document.write( "Let \"+b+\" = ml of solution 2 needed
\n" ); document.write( "----------
\n" ); document.write( "(1) \"+a+%2B+b+=+100+\"
\n" ); document.write( "(2) \"+%28+.8a+%2B+.3b+%29+%2F+100+=+.5+\"
\n" ); document.write( "---------------------------
\n" ); document.write( "(2) \"+.8a+%2B+.3b+=+.5%2A100+\"
\n" ); document.write( "(2) \"+.8a+%2B+.3b+=+50+\"
\n" ); document.write( "(2) \"+8a+%2B+3b+=+500+\"
\n" ); document.write( "Multiply both sides of (1) by \"+3+\"
\n" ); document.write( "and subtract (1) from (2)
\n" ); document.write( "(2) \"+8a+%2B+3b+=+500+\"
\n" ); document.write( "(1) \"+-3a+-+3b+=+-300+\"
\n" ); document.write( "\"+5a+=+200+\"
\n" ); document.write( "\"+a+=+40+\"
\n" ); document.write( "and
\n" ); document.write( "(1) \"+a+%2B+b+=+100+\"
\n" ); document.write( "\"+b+=+60+\"
\n" ); document.write( "40 ml of solution 1 is needed
\n" ); document.write( "60 ml of solution 2 is needed
\n" ); document.write( "------------
\n" ); document.write( "(c)
\n" ); document.write( "No. You can't get a greater % of benzene than
\n" ); document.write( "either of the 2 solutions have which is
\n" ); document.write( "80% and 30%\r
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\n" ); document.write( "\n" ); document.write( "
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