document.write( "Question 763418: I need to know what a parabola graph looks like when the parabola will cross the x-axis at 0 and 12. I worked out the problem I just need to know what the graph will look like. I don't understand that part of it.\r
\n" ); document.write( "\n" ); document.write( "My problem was: -25x^2 + 300x = 0
\n" ); document.write( " 25x^2 - 300x = 0
\n" ); document.write( " 25x (x - 12) = 0
\n" ); document.write( " 25x = 0 or x -12 = 0
\n" ); document.write( "I just need to know how to graph it and see what it looks like. I believe the parabola will open downward because it has a negative value.
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Algebra.Com's Answer #464788 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Here's the graph:
\n" ); document.write( "\"+graph%28+400%2C+400%2C+-4%2C+16%2C+-100%2C+1000%2C+-25x%5E2+%2B+300x+%29+\"
\n" ); document.write( "--------------
\n" ); document.write( "One thing to notice right away is it must go through
\n" ); document.write( "( 0,0 ) since making \"+x+=+0+\" will force \"+y+=+0+\"
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\n" ); document.write( "The x-crossings ( the roots ) are at ( 0,0 ) and ( 12,0 )
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\n" ); document.write( "The vertex is at \"+-b%2F%282a%29+\" when the equation has the form
\n" ); document.write( "\"+y+=+ax%5E2+%2B+bx+%2B+c+\"
\n" ); document.write( "For your equation:
\n" ); document.write( "\"+a+=+-25+\"
\n" ); document.write( "\"+b+=+300+\"
\n" ); document.write( "\"+c+=+0+\"
\n" ); document.write( "\"+-b%2F%282a%29+=+-300+%2F+%28+2%2A%28-25%29%29+\"
\n" ); document.write( "\"+-b%2F%282a%29+=+-300+%2F+%28-50%29+\"
\n" ); document.write( "\"+-b%2F%282a%29+=+6+\"
\n" ); document.write( "---------------
\n" ); document.write( "So, the vertex is at ( 6,y ) Now find \"+y+\"
\n" ); document.write( "\"+y+=+-25%2A6%5E2+%2B+300%2A6+\"
\n" ); document.write( "\"+y+=+-900+%2B+1800+\"
\n" ); document.write( "\"+y+=+900+\"
\n" ); document.write( "The vertex is at ( 6,900 )
\n" ); document.write( "The vertex is above the x-crossings, so it
\n" ); document.write( "must open down.\r
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